b) |→AB+→AC|
BK = q/2
x2+(a/2)2 = a2
x2+a2/4 = a2
x2 = a2-a2/4
x2 = a2(3/4)
x = ∓√a23/4 = √a23/√4 = √a2√3/2 = |a|√3/2 = a√3/2
AD = 2x = 2•a√3/2 = a√3
b) |→AB+→AC|
BK = q/2
x2+(a/2)2 = a2
x2+a2/4 = a2
x2 = a2-a2/4
x2 = a2(3/4)
x = ∓√a23/4 = √a23/√4 = √a2√3/2 = |a|√3/2 = a√3/2
AD = 2x = 2•a√3/2 = a√3